With autocad software
1.Draw any shape
2.Covert to poly line
3.Type region in command bar
4.Type massprop in command bar
5.Note down values of centroid(x,y) by pressing F2
6.Type line command
7.Input centroid values(X,y) in command bar
8.centroid of the particular shape can be located.
Tyr it
BEST OF LUCK
Each body has its own centre of gravity. The centre of gravity of two regular shapes - an equilateral triangle and a square will be different so why should the cog of a regular and an irregular shape not be different?
Because your body's centre of gravity is disrupted when you stand on one foot. Standing on both feet, your centre of gravity is equidistant from left to right.
The period of a pendulum is totally un-affected by the mass of the bob.The time period of pendulum is given by the eqn.T=2*PIE*(l/g)1/2 ;l is the length of pendulum;g is the acceleration due to gravity.'l' is the length from the centre of suspension to the centre of gravity the bob.ie.the length of the pendulum depends on the centre of gravity of the bob,and hence the distribution of mass of the bob.
It is the centre of the circle. The size of the radius makes no difference.
Centre of area of a triangle is the centre point for a circumscribed radius which will pass through all 3 vertices of the triangle.
The center of gravity of irregular objects can be measured by hanging the object freely and observing where it balances perfectly. Another method is to calculate the average position of the weight distribution in each dimension. Computer software can also be used to model the object and determine its center of gravity.
Each body has its own centre of gravity. The centre of gravity of two regular shapes - an equilateral triangle and a square will be different so why should the cog of a regular and an irregular shape not be different?
The center of gravity of an irregular object can be determined by finding the point where the object would balance perfectly in any orientation. This can be done by supporting the object at different points and adjusting until it is balanced. The center of gravity is typically the point where all these balancing points intersect.
If a force acts in a direction which passes through the centre of gravity of the object then it will impart no rotational acceleration; only linear acceleration.
The center of gravity of an irregular lamina is the point at which the entire weight of the lamina can be considered to act. It can be determined by balancing the lamina on a point and finding the point of equilibrium. Mathematically, it can be calculated by finding the weighted average of the x and y coordinates of all the points on the lamina.
Yes, the position of the Metacentre depends on the position of the centre of gravity. If the centre of gravity is above the Metacentre, the ship will be stable. If the centre of gravity is below the Metacentre, the ship will be unstable.
Centre for Software Reliability was created in 1983.
It isn't. Gravity can be viewed as emanating from the centre of a body with mass. As the distance increases from the centre then the gravity decreases.
As compared to Earth, you mean? If an object doesn't change its shape, the center of mass doesn't depend on gravity - and the center of gravity hardly does so.
The factors affecting the center of gravity of an object include its shape, mass distribution, and orientation relative to a reference point. Objects with irregular shapes or uneven mass distribution tend to have a less predictable center of gravity. Changes in the object's position or orientation can also affect the location of its center of gravity.
gravity is a force by which objects are attracted to the centre of.
Assuming the ball is a perfect sphere of uniform density, and is suspended from a massless string, the centre of gravity is in the centre of the ball.