There are a few cases in which legs have been amputated and prosthesis made, but this is very rare.
No
If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).
51 horses of which there are 3 cows with 2 heads and three legs or since there are no 3 legged cows there are 60 horses
If all the animals were horses there would be 360 legs. There is a shortfall of 23 which means 23 cows and therefore 67 horses.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
If all cows were four-legged there would be a total of 4 x 131 ie 524 legs. There are therefore 36 missing legs so there are 95 horses. (4 x 95 + 3 x 36 = 380 + 108 = 488 legs)
If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).
51 horses of which there are 3 cows with 2 heads and three legs or since there are no 3 legged cows there are 60 horses
If all the animals were horses there would be 360 legs. There is a shortfall of 23 which means 23 cows and therefore 67 horses.
Horses are quadrupeds, so they have 4 legs.
Bench kneed, sickle hocked, post legged.
yes.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
Do-it-in-your-head method: If all animals were horses there would be 4 x 46 ie 184 legs. There is a shortage of 31 legs which means there are 31 cows (and 15 horses). 31 x 3 = 93, 15 x 4 = 60 total 153. Shazam!
Horses Deer Squirrels
horses.....
If all cows were four-legged there would be a total of 4 x 131 ie 524 legs. There are therefore 36 missing legs so there are 95 horses. (4 x 95 + 3 x 36 = 380 + 108 = 488 legs)
Let's denote the number of horses as 'H' and the number of three-legged cows as 'C'. Each horse has one head and four legs, while each three-legged cow has one head and three legs. From the given information, we can form two equations: H + C = 129 (total number of heads) and 4H + 3C = 480 (total number of legs). By solving these two equations simultaneously, we can determine the number of horses on the farm.