That's a scalene triangle.
right angle triangle
No. With the given side lengths the sum of the two shorter sides do not exceed the length of the longest side and would not meet to form a triangle
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
Because all side lengths are different, it must be a scalene triangle.
That's a scalene triangle.
The Pythagorean theorem says; a^2 + b^2 = c^2 a = 6 b = 6 c = 10 6^2 + 8^2 = 100 could be a right triangle
If its a right angle triangle then its side lengths could be 3, 4 and 5
right angle triangle
No. With the given side lengths the sum of the two shorter sides do not exceed the length of the longest side and would not meet to form a triangle
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
Being a right-triangle, apply Pythagoras. Hence h^(2) = a^(2) + b^(2) Substitute h^(2) = 6^(2) + 8^(2) h^(2) = 36 + 64 h^(2) = 100 Square root BOTH sides. h = 10 (The length of the hypotenuse.
Because all side lengths are different, it must be a scalene triangle.
Yes. For example, place the 6 as the base, and the 3 and 4 sloping up from that base.
Yes
It is sqrt(6^2 + 5^2) = sqrt(36+25) = sqrt(61) = 7.8102, approx.
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