You can prove that 2K,2K,1-1 by first determining that the integer N can be written in the form of N=2K.
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6 + 2K = 11 subtract 6 from each side - 6 + 6 + 2K = 11 - 6 2K = 5 divide the integers both sides by 2 K = 5/2 check 6 + 2(5/2) = 11 6 + 10/2 = 11 6 + 5 = 11 11 = 11 checks
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Well, honey, if you want to solve for k, just isolate the variable by subtracting 3 from both sides of the equation. That leaves you with 2k equals 8. Then, divide both sides by 2 to find that k equals 4. Math doesn't have to be a headache, darling.
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Let even be of the form 2k and odd be of the form 2k+1. Then odd * even becomes 2k*2k+1, or 4k^2 +2k. This can be written as 2(k^2 + k), which is of the form 2k. Therefore, odd X even equals even.