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Q: Can someone prove that 2k 2k 1-1?

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It becomes: 2k squared

(2k + 3) (2k + 3)

35 + 2k = 9k subtract 2k from each side 35 + 2k - 2k = 9k - 2k 35 = 7k divide both sides integers by 7 35/7 = (7/7)k 5 = k check in original equation 35 + 2(5) = 9(5) 35 + 10 = 45 45 = 45 checks out

2k - 3k - m + 2m = -k + m

Add 17 to each side and collect like terms: 2k = 17 + 4 - 21k - 6 ie 2k = 15 - 21k so 23k = 15 which suggests that you may have mistyped your question.

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To prove that 2k 2k plus 1-1 by induction is a step by step process. But the induction 2 is not equal to 2 to the power of 0 take away 1.

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2k + 3 = 11(- 3 from both sides)2k = 8(divide both sides by 2)k = 4

Yes he is.

6 + 2K = 11 subtract 6 from each side - 6 + 6 + 2K = 11 - 6 2K = 5 divide the integers both sides by 2 K = 5/2 check 6 + 2(5/2) = 11 6 + 10/2 = 11 6 + 5 = 11 11 = 11 checks

Yes it is.

Is the following what you are claiming? 2k = 2k+1 -1 20 not equal 20+1 - 1 21 not equal 21+1 -1

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