No.
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
In the context of stars, a magnitude is not a measure of size but of brightness or apparent brightness. The apparent magnitude of the sun is -27 while Sirius, the brightest star has a magnitude of only -1.4: negative magnitudes are more bright, and stars with magnitudes greater than 6.5 are not visible to the naked eye. However, the sun is a star of modest modest size compared with some of the giants and supergiants.
yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....
Magnitude means size. The magnitude of 8 is greater than the magnitude of 4. The magnitude of 1023209138109283 is greater than the magnitude of 12. =)) .... enjoyy... =D
Not sure if you want just a positive and a negative integer, added or more info.2 positive integers a & b (easiest)a + b the result is positive.2 negative integers a & bAdd the magnitude of a and magnitude of b, the result is negative.Example -2 + -5 = -(2+5) = -(7) = -7a is positive, b is negative, take the difference of the magnitudes, thenif |a| (magnitude of a) greater than |b| (magnitude of b), the result is positive.if |a| (magnitude of a) less than |b| (magnitude of b), the result is negative.Example: 2 + -5 (the difference of magnitudes is 5-2 = 3The negative number has a bigger magnitude, so the answer is negative: -3-2 + 5The difference is still 3, but the positive number has bigger magnitude,so the result is positive: +3
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
No.
Large earthquakes (magnitudes greater than 8) are measured using the MMS (moment magnitude) scale. Small and moderate strength earthquakes (those with magnitudes less than 7) are measured using the Richter magnitude scale and earthquakes with magnitudes between 7 and 8 are measured using the Surface Wave magnitude scale.
The magnitude of the sum of any two vectors can be anywhere between zero and the sum of their two magnitudes, depending on their magnitudes and the angle between them. When you say "components", you're simply describing a sum of two vectors that happen to be perpendicular to each other. In that case, the magnitude of their sum is Square root of [ (magnitude of one component)2 + (magnitude of the other component)2 ] It looks to me like that can't be less than the the magnitude of the greater component.
A hundred times greater. The "magnitudes" used here use a logarithmic scale; every increase by one magnitude means an increase of the amount of energy in the earthquake by a factor of 10 in this case.
No, the magnitude of the resulting force when forces are combined is at MOST equal to the sum of forces, this is when they are all in the same direction. Else its magnitude will always be less than the sum of magnitudes of the individual forces involved (some forces will be oposing or "fighting" others).
In the context of stars, a magnitude is not a measure of size but of brightness or apparent brightness. The apparent magnitude of the sun is -27 while Sirius, the brightest star has a magnitude of only -1.4: negative magnitudes are more bright, and stars with magnitudes greater than 6.5 are not visible to the naked eye. However, the sun is a star of modest modest size compared with some of the giants and supergiants.
No, they could be equal If the two vectors are opposites (180 degrees apart) like r and -r, then the sum of their magnitudes is the magnitude of their sum. ?? North 1 plus East 1 gives NorthEast 1.414. North 1 plus South 1 gives 0. North 1 plus North 1 gives North 2, which is equal to, not less than 1+1.
yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....
Since January 1 2008, there have been more than three earthquakes that happened worldwide per day with magnitudes greater than 5.0
The apparent magnitude is how bright the star appears to us, but stars are all at different distances so that a star that is really bright might look dim because it is very far away. So the absolute magnitude measures how bright the star would look if it was placed at a standard distance of 10 parsecs. When the absolute magnitude is greater than the apparent magnitude, it just means that it is closer than 10 pc. The brightest stars have absolute magnitudes around -7.
Magnitude means size. The magnitude of 8 is greater than the magnitude of 4. The magnitude of 1023209138109283 is greater than the magnitude of 12. =)) .... enjoyy... =D