No.
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
In the context of stars, a magnitude is not a measure of size but of brightness or apparent brightness. The apparent magnitude of the sun is -27 while Sirius, the brightest star has a magnitude of only -1.4: negative magnitudes are more bright, and stars with magnitudes greater than 6.5 are not visible to the naked eye. However, the sun is a star of modest modest size compared with some of the giants and supergiants.
yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....
Magnitude means size. The magnitude of 8 is greater than the magnitude of 4. The magnitude of 1023209138109283 is greater than the magnitude of 12. =)) .... enjoyy... =D
Not sure if you want just a positive and a negative integer, added or more info.2 positive integers a & b (easiest)a + b the result is positive.2 negative integers a & bAdd the magnitude of a and magnitude of b, the result is negative.Example -2 + -5 = -(2+5) = -(7) = -7a is positive, b is negative, take the difference of the magnitudes, thenif |a| (magnitude of a) greater than |b| (magnitude of b), the result is positive.if |a| (magnitude of a) less than |b| (magnitude of b), the result is negative.Example: 2 + -5 (the difference of magnitudes is 5-2 = 3The negative number has a bigger magnitude, so the answer is negative: -3-2 + 5The difference is still 3, but the positive number has bigger magnitude,so the result is positive: +3
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
No.
Large earthquakes (magnitudes greater than 8) are measured using the MMS (moment magnitude) scale. Small and moderate strength earthquakes (those with magnitudes less than 7) are measured using the Richter magnitude scale and earthquakes with magnitudes between 7 and 8 are measured using the Surface Wave magnitude scale.
The magnitude of the sum of any two vectors can be anywhere between zero and the sum of their two magnitudes, depending on their magnitudes and the angle between them. When you say "components", you're simply describing a sum of two vectors that happen to be perpendicular to each other. In that case, the magnitude of their sum is Square root of [ (magnitude of one component)2 + (magnitude of the other component)2 ] It looks to me like that can't be less than the the magnitude of the greater component.
A hundred times greater. The "magnitudes" used here use a logarithmic scale; every increase by one magnitude means an increase of the amount of energy in the earthquake by a factor of 10 in this case.
Unless the vector is one dimensional, or only valued along one base in a multidimensional space, in which case the magnitude is equal to it's components, a vector's magnitude has to be greater than its components.
Yes, the magnitude of the difference between two vectors can be greater than the magnitude of either vector. This can occur when the vectors are in opposite directions or have different magnitudes such that the resulting difference vector is longer than either of the original vectors.
can a vector have a component greater than the vector magnitude
The acceleration with the larger magnitude is the one with a greater numerical value, regardless of its direction. Acceleration is a vector quantity, meaning it has both magnitude and direction, but when comparing magnitudes, only the numerical values are considered.
No, the magnitude of the resulting force when forces are combined is at MOST equal to the sum of forces, this is when they are all in the same direction. Else its magnitude will always be less than the sum of magnitudes of the individual forces involved (some forces will be oposing or "fighting" others).
In the context of stars, a magnitude is not a measure of size but of brightness or apparent brightness. The apparent magnitude of the sun is -27 while Sirius, the brightest star has a magnitude of only -1.4: negative magnitudes are more bright, and stars with magnitudes greater than 6.5 are not visible to the naked eye. However, the sun is a star of modest modest size compared with some of the giants and supergiants.
yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....