No, it is not possible.
The numbers are 3, and 4.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
hi
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
The square of 3 is 9, which does not lie between consecutive integers. Perhaps you mean the square root of 3, which lies between 1 and 2.
The numbers are 3, and 4.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
hi
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
9 and 10
The integers are 12 and 14 (144+196=340)
The square of 3 is 9, which does not lie between consecutive integers. Perhaps you mean the square root of 3, which lies between 1 and 2.
A square number is the product of the same two integers. A rectangular number is the product of consecutive integers.
The positive square root of 64 is exactly equal to 8.
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
two consecutive integers of the square root of 66 found between