No, it is not possible.
The numbers are 3, and 4.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
hi
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
The square of 3 is 9, which does not lie between consecutive integers. Perhaps you mean the square root of 3, which lies between 1 and 2.
The numbers are 3, and 4.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
hi
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
If you define a rectangular number as a number which is the product of two consecutive integers, it cannot be square.
9 and 10
The integers are 12 and 14 (144+196=340)
The square of 3 is 9, which does not lie between consecutive integers. Perhaps you mean the square root of 3, which lies between 1 and 2.
Consecutive square numbers are the squares of consecutive integers. For example, if you take the integers 1, 2, and 3, their squares are 1² = 1, 2² = 4, and 3² = 9, making 1, 4, and 9 consecutive square numbers. These square numbers differ by an increasing odd number: 4 - 1 = 3 and 9 - 4 = 5. Thus, the pattern continues as you square larger consecutive integers.
A square number is the product of the same two integers. A rectangular number is the product of consecutive integers.
The positive square root of 64 is exactly equal to 8.
two consecutive integers of the square root of 66 found between