The equation is 4x-3y=-12
The easiest way is to remember that the line will intersect the x axis when y is equal to 0.
So set y=0 and you have
4x=-12 or x=-3
Next, the line will intersect the y axis when x is 0
So set x=0 and you have
-3y=-12 or y=4.
As points, the x intercept is (-3,0)
and the y intercept is (0,4)
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.
x=3 y=2 z=6
The equation is equal to y = x-4. It has an infinite number of points. The intercepts are (4, 0) and (0, -4)
0-8
The 'x' and 'y' intercepts of that equation are both at the origin.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.
x = ±2
5 -8
x=3 y=2 z=6
The equation is equal to y = x-4. It has an infinite number of points. The intercepts are (4, 0) and (0, -4)
type you answer here!
0-8
A suitable equation for that would be y is equal to negative 2 times x plus five
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)