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Yes.

Given any set of n numbers it is always possible to fit a polynomial of order (n-1) that will generate the set of data.

For example, consider 2, 4, 8, 16, 32.

It is the sequence of numbers defined by

Un = 2n where n = 1, 2, 3, ...

But then consider Vn = (n4 - 6n3 + 23n2 - 18n + 24)/12 for n = 1, 2, 3, ...

These generate the same sequence for n = 1 to 5. Unless the data set is infinite, there is always the polynomial alternative. And that is not the only option.

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