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Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third.
That can indeed be done. For example:
(4i + 7)(3i + 2)
= -12 + 8i + 21i + 14
= 29i + 2
Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.
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Which binomial is a factor of x3-3x2 - 28x?
The expression does not have any real binomial factors. x is a monomial factor, and the other two involve complex numbers.
What is the relation of complex numbers to real numbers?
Complex numbers are a proper superset of real numbers. That is to say, real numbers are a proper subset of complex numbers.
Could anyone list numbers not in the set of complex numbers?
No. Complex numbers is the highest set of numbers you can go, and there are no sets outside of complex numbers.
Set of real numbers and set of complex numbers are equivalent?
Real numbers are a proper subset of Complex numbers.
What are the kinds of complex numbers?
Complex numbers include real numbers, pure imaginary numbers, and the combination of those two.
