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Aob has a measure of 90 and called a?
If the measurement is in degrees, it would be called a right angle.
Draw a involude for a semi circle of radius 25mm?
bisect a angle AOB 35
What is the length of arc AB if measured of AOB equals 240 and the radius is 4?
The equation for finding the length of an arc is S=rθ,where S is the arc length, r is the radius, and θ is the angle in radians.Assuming you mean AOB=240 is the angle of the arc you are measuring in degrees:θ=(pi*240)/180=4.1888radTherefore the arc length is 4cm*4.1888rad=16pi/3=16.76cm
The area of the region bounded by arc AB and line segment AB is found by taking the area of sector AOB and subtracting?
Unfortunately, I haven't been permitted to see the drawing thatgoes along with the question. But I guess that would make it tooeasy. Over here at WikiAnswers we're good, so I'll just answer itwithout the drawing:" . . . the area of triangle AOB."
Angle subtended by an arc is double the angle subtended by it at any other point on the remaining part of the circle?
You can prove this just from knowing that the three angles of a triangle add to 180 degrees. Label the ends of the arc A and B, the circle's centre O and the "any other point" P. We want to show that angle APB is half of angle AOB. (This uses the notation where you write three letters XYZ to mean the angle formed between straight lines XY and YZ). Consider the triangle formed by O, B and P. The lengths OB and OP are the same (the radius of the circle). This means that the triangle is isosceles and angles OPB and OBP are the same. Since POB + OPB + OBP = 180 degrees and OPB = OBP we have POB + 2 * OPB = 180 With the same working, the triangle formed by O, A and P gives us POA + 2 * OPA = 180 Subtract these two equations: (POB - POA) + 2 * (OPB - OPA) = 180 - 180 = 0 Rearrange: 2 * (OPB - OPA) = POA - POB If you draw a diagram you will see that OPB - OPA = APB and POA - POB = AOB so we have 2 * APB = AOB as required.
