525 = 3*5*5*7
3 with 14 remaining95 - 14 = 81 = 27 x 3
3(32) is 27 14(52) is 350 27 times 350 is 9450
3×5×5×7=525
525 = 3 x 5 x 5 x 7
The GCF is 3.
525 = 3*5*5*7
14 = 2 × 7 27 = 3³ → hcf(14, 27) = 1 → 14 and 27 are relatively prime.
2100
3 with 14 remaining95 - 14 = 81 = 27 x 3
175
3(32) is 27 14(52) is 350 27 times 350 is 9450
3 * 9 * 14
525 = 3*52*7
3×5×5×7=525
By: (3+3+3) times 3 = 27
525 = 3 x 5 x 5 x 7