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∙ 11y agoYes. 3+2+6=11. If you divide 11 and 3, your answer is 3r2. You will have two 3 inch sides and one 5 inch side.
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∙ 11y agoYou remove right angled triangles whose legs are 3*[2-sqrt(2)] = 1.7574 inches long.
Let's start at the beginning of the taper, where the opening is zero, and go out a foot until it opens to 3/4 inch. We have a long skinny triangle. The line down the middle is 1 ft long, the line that closes off the open end is 1-1/2 inches. The line down the middle divides the long skinny triangle into 2 back-to-back right triangles. Each one has a 12-inch leg and a 3/4-inch leg. The angle back at the pointy starting end of each triangle is half of the angle we're looking for. That [half]-angle is tan-1(.75/12) = tan-1(0.0625) = 3.576 degrees (rounded) The whole angle is 7.153 degrees (rounded)
That is impossible because it can only have 1 perpendicular line so if it has 2 it wouldn't be a triangle.
Then its not a triangle.
Let's assume the triangle has points A, B, and C. Method 1 (3 lines) Draw two lines across the triangle parallel to line segment AB. Now you have two trapezoids and one triangle. Draw another line from C to the any point on the closest of the two lines you just drew, splitting the triangle into two more triangles. Method 2 (2 lines) Draw one line across the triangle parallel to line segment AB. Now you have one trapezoid and one triangle. Draw a second line that passes through C and is perpendicular to AB, splitting the trapezoid into two trapezoids and the triangle into 2 triangles. Method 3 (3 lines) Draw one line from point C to any point on line segment AB. Then draw a line parallel to AC and one parallel to BC, but don't let them cross the line you just drew.
No. A triangle with 2-inch sides is not congruent with a triangle with 3-inch sides.
yes. 8+4>2
if the triangle is a right angle it has 2 perpendicular line segments.
You remove right angled triangles whose legs are 3*[2-sqrt(2)] = 1.7574 inches long.
Picture a square. now make a line connecting the two diagonal points. If bh is the volume of the rectangle, then we only have half a rectangle for each right triangle giving 1/2 *bh or bh/2. For any other traingle put the base parallel to the ground. Make a perpendicular line to the ground then you have two parts of a triangle divided at a vertex. Each of the these parts has a right angle. Make a second triangle of the same size and if you turn it into the two triangle fromt he first triangle and cut it apart, you can manipulate it to make a rectangle. The two triangles are a rectangle which is bh. divide by two to get one triangle so 1/2*bh or bh/2
The formula for area of a triangle is bh/2 b=base h=height /=divide so multiply the base(or the bottom) side by the height of the triangle, and then divide that by two.
No. The three vertices would all lie on one line.
Need the angle between those two sides, or some more info. Imagine taking a 1 inch tooth pick and a 2 inch toothpick. Now line up the tips and you can make tons of angles. If you joined the outer tips of your toothpicks you would have a triangle. Can you see that you can have many different sides lengths depending on the angle between them?
x=y is the diagonal line which runs through 0,0 so all you have to do is reflect the triangle on the diagonal line. hop that helps :)
Let's start at the beginning of the taper, where the opening is zero, and go out a foot until it opens to 3/4 inch. We have a long skinny triangle. The line down the middle is 1 ft long, the line that closes off the open end is 1-1/2 inches. The line down the middle divides the long skinny triangle into 2 back-to-back right triangles. Each one has a 12-inch leg and a 3/4-inch leg. The angle back at the pointy starting end of each triangle is half of the angle we're looking for. That [half]-angle is tan-1(.75/12) = tan-1(0.0625) = 3.576 degrees (rounded) The whole angle is 7.153 degrees (rounded)
the star of david
A standard water line PVC pipe typically has a width (diameter) of either 1/2 inch, 3/4 inch, 1 inch, or 1.5 inches.