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Oh, dude, there are like a bazillion different arrays you can make with 18. Okay, maybe not a bazillion, but definitely a lot. You can have arrays like [1, 2, 3, 4, 5, 6], [18], [9, 9], or even [2, 9, 7]. The possibilities are endless... well, not really, but you get the point.
If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.
9+9 and 9+9+9+9+9
7x9
8 has more factors.