For a binomial probability distribution, the variance is n*p*q which is 80*.3*.7 = 16.8. The standard deviation is square root of the variance which is 4.099; rounded is 4.1. The mean for a binomial probability distribution is n*p or 80*.3 or 24.
okay wikianswers messed up the question. H0: M=23; H1: M not 23; n=50; x-bar = 21.25; standard deviation = 5. please help!
There is insufficient information in the question to answer it. In order to compute a mean and a standard deviation, you need at least two data points, but the question only gave one. Please restate the question.
There is insufficient information in the question to properly answer it. In order to compute a Z score from a raw score, you need the mean and the the standard deviation, neither of which was given. Please restate the question.
To find the probability of a randomly selected woman's height, we can use the properties of the normal distribution. If women's heights are normally distributed with a mean (μ) of 64.1 inches and a standard deviation (σ) of 3.2 inches, we can calculate probabilities for specific ranges of heights using the Z-score formula: ( Z = \frac{(X - μ)}{σ} ). For a specific height or range, we can then look up the corresponding probability in standard normal distribution tables or use statistical software. Please specify the height or range you are interested in for a more precise calculation.
To find the probability of a randomly selected woman having a height within a specific range, we can use the normal distribution with the given mean (μ = 63.6 inches) and standard deviation (σ = 2.1 inches). For instance, if we want to find the probability that a randomly selected woman is shorter than 65 inches, we would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the height in question. After calculating the z-score, we would consult the standard normal distribution table or use a calculator to find the corresponding probability. If you have a specific height range in mind, please specify for a more detailed calculation.
No. Standard deviation is the square root of a non-negative number (the variance) and as such has to be at least zero. Please see the related links for a definition of standard deviation and some examples.
Yes. Please see the related link, below.
The cumulative probability up to the mean plus 1 standard deviation for a Normal distribution - not any distribution - is 84%. The reference is any table (or on-line version) of z-scores for the standard normal distribution.
okay wikianswers messed up the question. H0: M=23; H1: M not 23; n=50; x-bar = 21.25; standard deviation = 5. please help!
There is insufficient information in the question to answer it. In order to compute a mean and a standard deviation, you need at least two data points, but the question only gave one. Please restate the question.
It seems like your question contains a lot of random characters and may not be clear. If you're asking about "dispersion," it generally refers to the way in which data points are spread out or distributed in a dataset. This can involve concepts like variance, standard deviation, and range, which help to understand the variability within a set of values. Please clarify if you meant something specific!
This question cannot be answered. You need the mean and standard deviation in order to compute a Z score for a Raw score. Please restate the question.
There is insufficient information in the question to answer it. To determine Z score, you need raw score, mean, and standard deviation. Please restate the question.
In order to know the z-score, given a test score, you must also know the mean and the standard deviation. Please restate the question.
There is insufficient information in the question to properly answer it. In order to compute a Z score from a raw score, you need the mean and the the standard deviation, neither of which was given. Please restate the question.
A "c" is not a standard measure that we know. -please re-write when you know the measure.
To find the probability of a randomly selected woman's height, we can use the properties of the normal distribution. If women's heights are normally distributed with a mean (μ) of 64.1 inches and a standard deviation (σ) of 3.2 inches, we can calculate probabilities for specific ranges of heights using the Z-score formula: ( Z = \frac{(X - μ)}{σ} ). For a specific height or range, we can then look up the corresponding probability in standard normal distribution tables or use statistical software. Please specify the height or range you are interested in for a more precise calculation.