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How do you change slope intercept to standard form?
Slope intercept form: y = mx + c where m and c are constants. Subtract y from both sides: 0 = mx + c -y Rearrange: 0 = mx - y + c = standard form.
Where does y-3x plus 3 equals 0 cross the x axis?
rearrange: y = 3x - 3, which crosses the x-axis when y = 0, ie when x = 1
What is the slope of the graph of the equation 4x-3y equals 9?
First rearrange the equation into the form y = mx + c 4x - 3y = 9 3y = 4x - 9 y = (4/3)x - (9/3) Remember for y = mx + c that ' m ' the slope/gradient , and ' c ' is the y-intercept. Hence the slo[pe is (4/3) y- intercept is 9/3 = 3
What are the points of intersection of x - y equals 2 and x square - 4y square equals 5?
Rearrange the first equation to y = 2-x and then substitute this into the second equation to form the quadratic equation: -3y2+4y-1 = 0 and when solved y = 3 or y = 1/3 Points of intersection are: (3,1) and (2 and 1/3, 1/3)
How do you rearrange x equals y to the power of b so that y is the subject?
you cant
