999 999 999 990
12+999/1000 which can be reduced to 12999/1000
921 and 129
936. All numbers divisible by 12 and 13 are multiplies of the lowest common multiple of 12 and 13 which is 156. 999 ÷ 156 = 621/52 ⇒ greatest multiple of 156 not bigger than 999 is 6 x 156 = 936.
$232.90
999 999 999 990
Archduchess Maria Leopoldine of Austria-Este was born on 1776-12-10.
it will cost 999$
Suppose f = 0.324324... Then 1000*f = 324.324324... Subtracting the first from the second gives 999*f = 324 Therefore f = 324/999 = 12/37
Exactly twelve zeros.
12+999/1000 which can be reduced to 12999/1000
Battle of Glenmama happened on 999-12-30.
Adelaide of Italy died on 999-12-16.
921 and 129
936. All numbers divisible by 12 and 13 are multiplies of the lowest common multiple of 12 and 13 which is 156. 999 ÷ 156 = 621/52 ⇒ greatest multiple of 156 not bigger than 999 is 6 x 156 = 936.
9.87654432110999999999999999012345567889 × 10^38 or 987 undecillion, 654 decillion, 432 nonillion, 110 octillion, 999 septillion, 999 sextillion, 999 quintillion, 999 quadrillion, 999 trillion, 12 billion, 345 million, 567 thousand 889. To figure it, rewrite 999999999999999999999999999 as 1000000000000000000000000000 - 1. Then figure (1000000000000000000000000000 - 1) x 987654432111 = 987654432111000000000000000000000000000 - 987654432111, which after subtracting, you get: 987,654,432,110,999,999,999,999,999,012,345,567,889 (the answer above).
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