Source program
LXI SP, 27FFH ; Initialize stack pointer
LDA 2200H ; Get the number
CPI 02H ; Check if number is greater than 1
JC LAST
MVI D, 00H ; Load number as a result
MOV E, A
DCR A
MOV C,A ; Load counter one less than number
CALL FACTO ; Call subroutine FACTO
XCHG ; Get the result in HL
SHLD 2201H ; Store result in the memory
JMP END
LAST: LXI H, 000lH ; Store result = 01
END: SHLD 2201H
HLT
Subroutine Program:
FACTO:LXI H, 0000H
MOV B, C ; Load counter
BACK: DAD D
DCR B
JNZ BACK ; Multiply by successive addition
XCHG ; Store result in DE
DCR C ; Decrement counter
CNZ FACTO ; Call subroutine FACTO
RET ; Return to main program
The most significant difference between the Intel 8085 and 8086 microprocessors is that the 8085 is an 8-bit system and the 8086 is a 16-bit system. This difference allows the 8086 system to have a much larger set of operational instructions and can make calculations to more significant places. Note: the 8085 processor does have two 16-bit registers. The pointer and the program counter.
sample program in sum of the series using the formula for s=n/2[2a+{n-1}d] in 8085
In the 8085, if the accumulator starts as 00H, then adding 89H and 79H to it results in a value of 02H with CARRY set.
The factors of 8085 are 1, 3, 5, 7, 11, 15, 21, 33, 35, 49, 55, 77, 105, 147, 165, 231, 245, 385, 539, 735, 1155, 1617, 2695, and 8085 8085 = 3*5*7*7*11, so the prime factors are 3, 5, 7 and 11. 7 is used twice!
The name 8085 was given to the next generation of the 8080 to indicate 1.) that it was a next generation device and 2.) that it only required a single +5V power supply to operate.
it is the standard usded by the INTEL to categorize their microprocessors.
There is no exit instruction in the 8085. Do you mean return, as in from a function or interrupt? If so, the instruction is RET.
Ten microprocessors are the 4004, 4040, 8008, 8080, 8085, 8086, 8088, 80286, 80386, and 80486.There are many more, and this list only included some of the Intel microprocessors, in mostly historical order.
E.g. 8085, 8086, 8255, 8051, 6800, 8257, 8251 and many more...
It's up to you: don't use it, if you don't want.
The most significant difference between the Intel 8085 and 8086 microprocessors is that the 8085 is an 8-bit system and the 8086 is a 16-bit system. This difference allows the 8086 system to have a much larger set of operational instructions and can make calculations to more significant places. Note: the 8085 processor does have two 16-bit registers. The pointer and the program counter.
VHDL is a hardware description language. It describes the functionality of a hardware as a program. If we know the architecture of 8085, the same can be implemented or coded using VHDL.
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
sample program in sum of the series using the formula for s=n/2[2a+{n-1}d] in 8085
Neither the 8155 nor the 8255 are considered to be microprocessors. The 8155 is an integrated RAM, IO, and Timer device designed for the 8085. The 8255 is an Programmable IO controller.
It starts with the 4004 chipset (4 bit) and 8008 microprocessor (8 bit). The successor of the 4004 was the 4040, but this architecture was a dead end. The successors of the 8008 were the 8080, 8085, 8086, 8088, 80186, 80286, 80386, 80486, Pentium, etc. including the current multicore microprocessors. IBM chose to base their PC on the 8086 and 8088, then as successive newer microprocessors were developed new versions of the IBM PC used those microprocessors. Intel also produced many specialized microprocessors and microcontrollers including some RISC microprocessors (e.g. i860, i960). Current Apple Macintosh computers also use the latest Intel multicore microprocessors.
4 T-states as usual and 2 more are required to perform n*8 its result gives the vector address of interrupt service routine(rstn is an software interrupt)