Consider a population with a mean of 63.3 and a standard deviation of 3.82 and a score of 61.6. Calculate the z-score for 61.6 from a sample of size 19?

Answer 1

Mean μ = 63.3

Standard deviation σ = 3.82

Standard error σ / √ n = 3.82 / √ 19 = 0.8763681

z = (xbar - μ) / (σ / √ n )

z = (61.6-63.3) / 0.876368

z = -1.9398