Best Answer

Mean μ = 63.3

Standard deviation σ = 3.82

Standard error σ / √ n = 3.82 / √ 19 = 0.8763681

z = (xbar - μ) / (σ / √ n )

z = (61.6-63.3) / 0.876368

z = -1.9398

Q: Consider a population with a mean of 63.3 and a standard deviation of 3.82 and a score of 61.6. Calculate the z-score for 61.6 from a sample of size 19?

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The standard deviation of the population. the standard deviation of the population.

Square the standard deviation and you will have the variance.

Yes

No.

You need more than one number to calculate a standard deviation, so 9 does not have a standard deviation.

Related questions

=stdev(...) will return the N-1 weighted sample standard deviation. =stdevp(...) will return the N weighted population standard deviation.

The standard deviation of the population. the standard deviation of the population.

we calculate standard deviation to find the avg of the difference of all values from mean.,

You calculate the standard error using the data.

Square the standard deviation and you will have the variance.

Standard error of the sample mean is calculated dividing the the sample estimate of population standard deviation ("sample standard deviation") by the square root of sample size.

Yes

No.

You need more than one number to calculate a standard deviation, so 9 does not have a standard deviation.

Standard deviation = square root of variance.

The standard deviation if the data is a sample from a population is 7.7115; if it is the population the standard deviation is 7.0396.

You can calculate standard deviation by addin the numbers of data that are together and dividing that number by the amount pieces of data.THAT IS TOTALLY INCORRECT.What was answered above was the calculation for getting an (mean) average.If you take five numbers for example 1, 2, 3, 4, 5 then the (mean) average is 3.But the standard deviation between them is 1.58814 and the variance is 2.5Also the population std. deviation will be 1.41421 and the population variance will be 2.see standard-deviation.appspot.com/