6.6 x 10-9
To find the (K_b) for NH2OH, you can use the relationship (K_w = K_a \times K_b). Solving for (K_b), we have (K_b = \frac{K_w}{K_a} = \frac{1.0 \times 10^{-14}}{1.5 \times 10^{-6}} = 6.67 \times 10^{-9}). So, the (K_b) for NH2OH at this temperature is (6.67 \times 10^{-9}).
The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+
It all depends on the molarity of the solution.
yes
polar
NH2OH is a covalent compound. It contains covalent bonds formed between nitrogen and hydrogen atoms.
Tetrahedral
There is no such compound, NH3 is basic and somethimes written as aquous solution of NH4OH
using cu and NH2OH at 250 C
To prepare a 0.5 M hydroxylammonium chloride solution, you would dissolve the appropriate amount of NH2OH-HCl in a specific volume of water. Calculate the moles of NH2OH-HCl needed (Molarity x Volume) and dissolve it in water to make the desired volume. Always remember to handle the compound with care due to its toxicity and reactivity.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
The oxidation number of N in NH2OH is -1. This is because each hydrogen atom has an oxidation number of +1, and oxygen usually has an oxidation number of -2. Since the overall molecule has a neutral charge, nitrogen must have an oxidation number of -1 to balance out the charges.