To find the (K_b) for NH2OH, you can use the relationship (K_w = K_a \times K_b). Solving for (K_b), we have (K_b = \frac{K_w}{K_a} = \frac{1.0 \times 10^{-14}}{1.5 \times 10^{-6}} = 6.67 \times 10^{-9}). So, the (K_b) for NH2OH at this temperature is (6.67 \times 10^{-9}).
The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+
The pH of NH2OH (hydroxylamine) is neutral, around 7, because it is a weak base that partially dissociates in water to form NH2OH+. OH- ions.
yes
polar
NH2OH is a covalent compound. It contains covalent bonds formed between nitrogen and hydrogen atoms.
Tetrahedral
There is no such compound, NH3 is basic and somethimes written as aquous solution of NH4OH
using cu and NH2OH at 250 C
To prepare a 0.5 M hydroxylammonium chloride solution, you would dissolve the appropriate amount of NH2OH-HCl in a specific volume of water. Calculate the moles of NH2OH-HCl needed (Molarity x Volume) and dissolve it in water to make the desired volume. Always remember to handle the compound with care due to its toxicity and reactivity.
The oxidation state of nitrogen in NH2OH is -1. The total charge on NH2OH is 0 and we know that the two hydrogens in NH2OH will be assigned an oxidation state of +1 each. By considering that oxygen has an oxidation state of -2, we can calculate the oxidation state of nitrogen to be -1.
The oxidation number of N in NH2OH is -1. This is because each hydrogen atom has an oxidation number of +1, and oxygen usually has an oxidation number of -2. Since the overall molecule has a neutral charge, nitrogen must have an oxidation number of -1 to balance out the charges.