To convert the binary number 10100 to base 10, we use the positional notation method. Starting from the right, we assign powers of 2 to each digit: 02^0 + 02^1 + 12^2 + 02^3 + 1*2^4 = 0 + 0 + 4 + 0 + 16 = 20. Therefore, the binary number 10100 is equivalent to the decimal number 20.
Oh, what a happy little question! To convert the binary number 10100 to base 10, you simply add the decimal values of the positions where 1s appear. So, it's 1 * 2^4 + 0 * 2^3 + 1 * 2^2 + 0 * 2^1 + 0 * 2^0, which equals 16 + 0 + 4 + 0 + 0, giving you a base 10 value of 20. Just like painting a beautiful landscape, it's all about taking it step by step and enjoying the process!
Oh, dude, you want me to do math? Fine, fine. So, to convert 10100 base 2 to base 10, you just take each digit and multiply it by 2 raised to the power of its position from right to left. So, it's like 1 x 2^4 + 0 x 2^3 + 1 x 2^2 + 0 x 2^1 + 0 x 2^0, which simplifies to 16 + 4 = 20. Easy peasy, right?
101002 = 1*24 + 0*23 + 1*22 + 0*21 + 0*20
(note the coefficients of the powers of 2 are the digits of the number in base 2).
=1*16 + 0*8 + 1*4 +0*2 +0*1 = 16+4 = 20
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
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The area of a trapezoid is equal to half the sum of the lengths of the two parallel sides (base1 and base2) multiplied by the height. The formula for the area of a trapezoid is A = (base1 + base2) * height / 2.
To add these two binary numbers, we can first convert them to decimal. 111111 in base 2 is equal to 63 in base 10, and 10001 in base 2 is equal to 17 in base 10. Adding these two decimal numbers gives us 63 + 17 = 80 in base 10. Finally, we convert 80 back to binary to get the final answer, which is 1010000 in base 2.
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
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11101010.1
The area of a trapezoid is equal to half the sum of the lengths of the two parallel sides (base1 and base2) multiplied by the height. The formula for the area of a trapezoid is A = (base1 + base2) * height / 2.
To add these two binary numbers, we can first convert them to decimal. 111111 in base 2 is equal to 63 in base 10, and 10001 in base 2 is equal to 17 in base 10. Adding these two decimal numbers gives us 63 + 17 = 80 in base 10. Finally, we convert 80 back to binary to get the final answer, which is 1010000 in base 2.
If it is a right angled triangle then this is known as Pythagoras' theorem: height2+base2 = hypotenuse2 ⇒ hypotenuse = √(height2 + base2)
Each of its parallel sides is classed as a base
struct base1 { // ... }; struct base2 { // ... }; struct derived1 : public base1 // single inheritance { // ... }; struct derived2 : public base1, public base2 // multiple inheritance { // ... };
(base1 + base2)/2 = midsegment
A trapezoid is a two-dimensional object. 2d objects do not have volume. To calculate the area, see below. With the parallel sides as base1 and base2, and the distance between them as the height: height*(base1+base2)/2
Another name for base2 math is binary math.
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared