If this is a homework assignment, please consider trying it by yourself first, otherwise the added value of reiforcement of the lesson due to actually doing the homework will be lost on you.
To convert any number from one base to another base, iteratively divide by the second base, using the rules of arithmetic for the first base, and write down the remainders in reverse order, until the quotient is zero. In this example, converting 52446 into 100100111002, the process is as follows...
5244 / 2 = 2422 remainder 0 (Remember, this is all in base 6 arithmetic!)
2422 / 2 = 1211 remainder 0
1211 / 2 = 0403 remainder 1 (Keeping the leading zeros to align the columns.)
0403 / 2 = 0201 remainder 1
0201 / 2 = 0100 remainder 1
0100 / 2 = 0030 remainder 0
0030 / 2 = 0013 remainder 0
0013 / 2 = 0004 remainder 1
0004 / 2 = 0002 remainder 0
0002 / 2 = 0001 remainder 0
0001 / 2 = 0000 remainder 1 (Stopping because the quotient is now zero.)
Look at the remainders above in reverse order, and you will see 10010011100.
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2406 = 2*62 + 4*6 = 9610 = 110 00002
The number 6 in binary is 110, which means that it is made up of 1 (4) + 1 (2) + 0 (1)
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
Decimal number 310 is equivalent to (1234) to the base 6
Convert each "digit" of the octal into a triplet of binary digits, according to the following rule: Octal Binary 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 So, for example, octal 53 = binary 101 011 [= decimal 43]