If this is a homework assignment, please consider trying it by yourself first, otherwise the added value of reiforcement of the lesson due to actually doing the homework will be lost on you.
To convert any number from one base to another base, iteratively divide by the second base, using the rules of arithmetic for the first base, and write down the remainders in reverse order, until the quotient is zero. In this example, converting 52446 into 100100111002, the process is as follows...
5244 / 2 = 2422 remainder 0 (Remember, this is all in base 6 arithmetic!)
2422 / 2 = 1211 remainder 0
1211 / 2 = 0403 remainder 1 (Keeping the leading zeros to align the columns.)
0403 / 2 = 0201 remainder 1
0201 / 2 = 0100 remainder 1
0100 / 2 = 0030 remainder 0
0030 / 2 = 0013 remainder 0
0013 / 2 = 0004 remainder 1
0004 / 2 = 0002 remainder 0
0002 / 2 = 0001 remainder 0
0001 / 2 = 0000 remainder 1 (Stopping because the quotient is now zero.)
Look at the remainders above in reverse order, and you will see 10010011100.
2406 = 2*62 + 4*6 = 9610 = 110 00002
The number 6 in binary is 110, which means that it is made up of 1 (4) + 1 (2) + 0 (1)
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
Decimal number 310 is equivalent to (1234) to the base 6
Convert each "digit" of the octal into a triplet of binary digits, according to the following rule: Octal Binary 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 So, for example, octal 53 = binary 101 011 [= decimal 43]
2406 = 2*62 + 4*6 = 9610 = 110 00002
Example Binary 00111000 Convert to Decimal 56 Convert to BCD by using groups of four binary numbers for each digit 5 6 0101 0110
The number 6 in binary is 110, which means that it is made up of 1 (4) + 1 (2) + 0 (1)
To convert from one base to another: 1) divide the number by the new base (in the original base) to get a [whole] quotient and remainder; 2) note the remainder; 3) replace the number by the quotient; 4) if the number is not zero repeat from step 1; 5) write the remainders out in reverse order to get the number in the new base; Converting 105 base 10 to binary (base 2): 105 ÷ 2 = 52 r 1 52 ÷ 2 = 26 r 0 26 ÷ 2 = 13 r 0 13 ÷ 2 = 6 r 1 6 ÷ 2 = 3 r 0 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 105 is 1101001 in binary.
Group the binary into 4's. For example:0110110101100110 1101 01106 D 6
In binary numbers....5 = 1016 = 1108 = 1000
This Binary Wil Be Equivalent to 629760 in decimal.
I would convert to base 10 , multiply and then convert back to base 6. 35 base 6 is 3 * 6 + 5 = 23 in base ten. 4 * 23 = 92 which is 2*36 + 3* 6 + 2 , in base 6 , the answer is 232 .
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
Decimal number 310 is equivalent to (1234) to the base 6
110 in decimal = 1101110 in binary (base 2). Interesting that the decimal value 110 is read in there twice! If you actuall meant the question "What is 110 in binary equivalent to in decimal?" then the answer is 4+2=6.
Convert each "digit" of the octal into a triplet of binary digits, according to the following rule: Octal Binary 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 So, for example, octal 53 = binary 101 011 [= decimal 43]