Solution: Since, the prime factors of 46 are 2, 23. Therefore, the product of prime factors = 2 × 23 = 46.
46 of them because 46/2 = 23forty-six46 x 0.5 = 23
102÷46 = 2 remainder 10
2 and 23
23
1 2 23 46.
2
The positive whole numbers are 1, 2, 23, and 46.1, 2, 23, 46.
1, 2, 4, 23, 46, 92
Exactly 23 times !
Oh, dude, like, 92 is made up of 90 and 2. It's like basic math, you know? So, if you're asking what numbers make up 92, it's just 90 and 2. Easy peasy lemon squeezy.
46 multiplied by 2 (46 • 2 or 46 x 2) equals 92.
1, 2, 4, 23, 46, 92.
46 times... with a remainder of 2 !
As many times as you want. If what you mean is, how many times can you subtract 2 from 46 before you hit zero (that is, "how many times does two go into 46") the answer is 23.
The factors of 46 are 1, 2, 23 and 46. The factor pairs of 46 are 1 x 46, and 2 x 23.Since 46 ends with a multiple of 2, it is divisible by 2. Divide it by 2 to find the other factor.
2 + 46 = 48