Nice data. What's your question ?
Could you possibly be asking for the frequency ???
Xc = 1 / (2 pi f C)
f = 1 / (2 pi Xc C)
= 106 / (2 pi Xc 0.15)
= 106 / (600.264)
= 1665.9 Hz (rounded)
Wiki User
∙ 14y agoone egg equals 2 oz. so 144 Ct * 2 oz. = 288 oz.
Sales tax on 2,500 dollars in Ct.
CT is the abreviation for carats. This weighing unit is used for weighing diamonds and other gemstones.
ct
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The difference in between Ohms and Ohms CT is that in Ohms CT it has CT at the end.
ZT=1/3 of CT. Therefore, CT=5
the amazon equals the copy ct which means
11 Players in a Cricket Team
one egg equals 2 oz. so 144 Ct * 2 oz. = 288 oz.
The letters CT stand for carat, the weight measurement for diamonds. One full carat -- 1.00 CT -- weighs .02 grammes. A diamond weighing 0.010 carat equals one one-hundredth of a carat.
ArkansasUTC-06 CT IllinoisUTC-06 CT IowaUTC-06 CT LouisianaUTC-06 CT MinnesotaUTC-06 CT MississippiUTC-06 CT MissouriUTC-06 CT OklahomaUTC-06 CT WisconsinUTC-06 CT
The air distance from Liverpool, England, to Waterbury, Connecticut, is 3,241 miles. That equals 5,215 kilometers or 2,816 nautical miles.
You mean CT. CT means Connecticut the abbreviation for Connecticut is CT get it?
CT (current transformer) Burden is the maximum load that the CT secondary can drive (e.g. meters or protection relays) Why do you care about burden when ordering current transformers? The burden is the termination impedance of the measuring instrument. The measuring instrument can be an analog or digital energy meter, a data logger or a recorder. All instruments that use a current transformer to measure line current must terminate the CT with a resistance (impedance in same case which means there is some inductance involved). A CT supplier should be given the burden when ordering. Technically, the total burden for a CT is the internal winding resistance, the connecting lead resistance and the measuring instrument input resistance. Some Ct's are installed a long distance from the measuring instrument and the connecting leads can have a resistance as much as 0.002 ohms per foot (both ways because the current makes a complete round trip). This resistance will cause an error if not taken into account.
This can be done, but is usually not done because a metering CT is made to be very accurate at expected load current levels. A protection CT is made to be accurate at fault current levels (which is often significantly above load current). If the CT is too small, and has too small of a ratio, the CT will likely saturate, which will skew the results the protective device expects to get. An example: a metering CT may have a ratio of 100:5 (made for 100A load current, which will produce 5 amps secondary current). Fault current levels may be ~10,000A. You'd expect the secondary output of a perfectly linear CT to be 500A. One way resistance of the cable connecting the protective device to the CT may be on the order of .5 - 2 ohms. Ignoring the resistance of the CT and connected devices, secondary voltages would reach 250 - 1,000 volts for a phase fault, and 500 - 2,000 volts for a ground fault. The biggest CTs may be rated for 800 volts output below the knee point, so this 100:5 CT would clearly saturate. The real output current would likely be on the order of 150A at the most. ...And the above is ignoring any DC offset, which would cause the CT to saturate at unpredictable AC current levels.
Half of CT,no. Half of CT, yes