Q size to order : obej. to find best of Q to minimize the cost
K:setup cost
c:cost of one unit
h: holding cost for one unit per one unit period of time
landa = demand rate
T cycle length = Q/landa
The cost is = order cost + cost of all unit ordered + average holding cost
C=K+cQ+(ThQ)/2
we divided all over time to be per unit time
so the average cost is :
G= (K+cQ)/T + (hQ/2)
replace T=Q/landa
G= ((K+cQ) / (Q/landa)) + (Qh/2)
then by manipulating
G= ((K* landa )/Q) + ( landa* c)+ (hQ/2)
this formula represent period setup cost , period purchases cost and period holding cost respectively.
because we want to find the minimize this formula gives we need to take the derivative -using calculus- to respect of Q:
G' = (- k *landa / Q^2) + h/2 - give min and max -
taking 2nd derivative
G'' = (2*k*landa)/Q^3
for Q>0 => G''>0 => G' is the min
having G' = 0
G' = (- k *landa / Q^2) + h/2 = 0
( k *landa / Q^2) = h/2
=> Q^2= (2*k*landa)/h
by taking square root of both sides
Q# (EOQ)= sqrt [(2*k*landa)/h]
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