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How are parallelogram related to triangles and rectangles?
If you draw one diagonal across a parallelogram, it will split it into two congruent triangles. A rectangle is a parallelogram, with all four angles equal to 90°.
Does the diagonals of a parallelogram bisect the angles?
No, the diagonals of a parallelogram do not necessarily bisect the angles. The diagonals of a parallelogram divide it into four congruent triangles, but they do not necessarily bisect the angles of those triangles.
Does A diagonal of parallelogram intersects all four sides?
Yes: The intersection is at one end of each side. This is true for a diagonal of any quadrilateral.
Does a parellelogram have four congruent triangles?
Yes. Read on for why: Take a parallelogram ABCD with midpoints E and F in the bases. So something like this (forgive the "drawing"): A E B __.__ /__.__/ C F D We know that parallelogram AEFC = EBDF, since they have the same base (F bisects CD, so CF = FD), height (haven't touched that), and angles (<ACF = <EFD because they're parallel - trust me that everything else matches). We also know that every parallelogram can be divided into two congruent triangles along their diagonal. So if two congruent parallelograms consistent of two congruent triangles each, then all four triangles are congruent. So your congruent triangles are ACF, AEF, EFD, and EBD. You can further reinforce this through ASA triangle congruency proofs (as I did at first), but this is a far more concise and equally valid answer.
Which polygon can be divided into 4 triangles?
A polygon that can be divided into 4 triangles is a quadrilateral. A quadrilateral is a polygon with four sides and four vertices. By drawing a diagonal from one vertex to the opposite vertex, a quadrilateral can be divided into two triangles. By drawing another diagonal from the other two vertices, the quadrilateral can be further divided into a total of four triangles.
