Yes, the diagonals of a rhombus are perpendicular to each other. Check out the related link at Mathopenref. It's pretty cool.
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
No but its diagonals are perpendicular to each other
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
rhombus and a square
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
It has two diagonals, and they are perpendicular to each other.
No but its diagonals are perpendicular to each other
perpendicular and bisect each other
Perpendicular bisectors of each other.
The diagonals of a rhombus are perpendicular to each other and are bisected at 90 degrees
The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
rhombus and a square
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
A rhombus. (A square is, of course, also a rhombus.)
The 2 diagonals of a rhombus are perpendicular and they intersect each other at right angles