The 9mm round measures .356 inch in diameter. a 380 is 95 gr 9mm 124gr 40 is180 gr 45 is 230 gr
Circumference = pi * diameter = 3.14159 * 11.6 = 36.44 Rounded to the nearest ten, that is 40 units.
Caliber is a term used to describe the diameter of a bullet in SAE units. 100 Caliber = 1 inch a 45 caliber bullet has a diameter of .45 inches.
Twice pi multiplied by the radius will get you the result. Pi, if you are going to round to the inch, call it 3.14. The radius will be half the diameter...20 inches. Find a calculator and multiply 2 X 3.14 X 20...you can do it. You can also multiply pi times the diameter and get the same result.
You take the radius (or diameter). If radius you times it by two (since it is half of the Diameter) then times the answer by 3.14. If diameter, times the diameter by 3.14. then round the decimals.
Caliber is in reference to the diameter of the bullet. A .40 (which is what I have) is .40 inches in diameter. A .50 caliber is .50 inches in diameter (half an inch). So a caliber is the inches in diameter. Not including the 9mm which I cannot stand
Yes, a 45 caliber bullet is bigger than a 40 caliber bullet. A .45 is0.45 inches wide in diameter and a .40 is 0.4 inches in diameter.
.40 S&W cartridge, bullet diameter = .401" .380 ACP cartridge, bullet diameter = .355-.356" .32 ACP cartridge, bullet diameter = .311 - .312"
The 9mm round measures .356 inch in diameter. a 380 is 95 gr 9mm 124gr 40 is180 gr 45 is 230 gr
Caliber means the diameter of the bullet. A .40 caliber cartridge has a bullet that is .40 inches in diameter. A 9mm cartridge has a bullet that is 9 millimeters in diameter. Yup...reminds me of Joe the Human Cannonball at the circus...Poor Joe died but they couldn't find a replacement of his caliber.
The .40 is a larger diameter round. The projectile has a dimension of .4005, versus the 9mm Parabellum, which has a dimension of .356. Of the two, the .40 is the more powerful cartridge.
The .40 is larger in diameter and (normally) has a heavier bullet.
Either platform can be larger than the other. The 45 has the larger projectile. Caliber is defined as the diameter in fractions of an inch, so .40 caliber is smaller in diameter than .45 caliber. Caliber can also be defined in the metric system, measured in milimeters. The .40 caliber cartridge is equivalent to 10mm in diameter. As noted, the size of a handgun can vary widely within one caliber, so it is perfectly reasonable to have a smaller handgun crafted in a larger caliber.
In excess of a mile.
Assuming the question is in regard to firearms and ammunition, you can read the "caliber" of a round as a decimal how wide the bullet is in inches. So a .40 caliber round is .4 inches wide, or about 10.16 millimeters wide. A .45 caliber round would be .45", so a little bit fatter than the .40 caliber round. The caliber doesn't tell the whole story of a round though, it doesn't say how long the bullet is, how heavy, how big the casing behind the round is, how much kinetic energy is hits with, etc. The .40 S&W round has an average of 425 ft/lbs of energy right at the muzzle, while the .45 ACP, a "bigger" round, has about 400 ft/lbs.
They're both measurements of the diameter of the round (or the barrel). Caliber is a measurement in inches, and millimeters are millimeters. For instance, a .30 caliber bullet is 30 hundredths of an inch, or 7.62 millimeters in diameter.
The radius of a .68 caliber paintball round is half of its diameter. Since the caliber is given in inches, the radius would be 0.34 inches.