dy/dx = a
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y=ax y'=ln(a)*ax
If y = ax and a = 0, then y=0. No matter what x is, y is still 0. Therefore any graph of y=ax (where a=0) will simply be a line at y=0, which is the x-axis.
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
a function
y' = (sec(x))^2