answersLogoWhite

0

The answer is 174.

DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIV

DXXII/III =
= D/III + X/III + X/III + II/III =
= (CxV)/III + (III + I/III) + (III + I/III) + II/III =
= Cx(V/III) + VII + I/III =
= Cx(I + II/III) + VII + I/III =
= C + (CxII)/III + VII + I/III =
= C + ((XxX)xII)/III + VII + I/III =
= C + Xx(XxII)/III + VII + I/III =
= C + Xx(VI + II/III) + VII + I/III =
= C + LX + (XxII)/III + VII + I/III =
= C + LX + VI + II/III + VII + I/III =
= CLXXIV
User Avatar

Wiki User

15y ago

What else can I help you with?