Angle abc will form a right angle if and only if, segment ab is perpendicular to segment bc.
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The sum of the internal angles of a triangle is 180º. If B is a right angle it has 90º, so there are only 90º left for the other two angles, meaning that they cannot be right!
The sum of the two angles is 360. So angle ABC = 120 degrees.
Let the sides be abc and their opposite angles be ABC and so: Using the cosine rule angle A = 67.38 degrees Using the cosine rule angle B = 67.38 degrees Angle C: 180-67.38-67.38 = 45.24 degrees
To find the measure of angle ABD, you can add the measures of angles ABC and CBD since they share a ray. Therefore, the measure of angle ABD is 40° + 23° = 63°. Thus, the measure of angle ABD is 63 degrees.
Let the Isosceles Triangle be ∆ ABC with sides AB = AC = 14', and BC = 17' Draw a line bIsecting angle BAC. This line will be perpendicular to and bisect BC at point D. Then ∆ DBA (or ∆ DCA) is a right angled triangle with AB the hypotenuse. Angle ABD = Angle ABC is one of the two equal angles of the isosceles triangle. Cos ABD = BD/AB = 8.5/14 = 0.607143, therefore Angle ABC = 52.62° The third angle of the triangle is 180 - (2 x 52.62) = 180 - 105.24 = 74.76° The angles are therefore 52.62° , 52.62° and 74.76° .