Yes they do.
To calculate the total number of legs, we consider each animal's legs: cows have 4 legs each, chickens have 2 legs each, fish have no legs, and ants have 6 legs each. For 3 cows, that's 3 x 4 = 12 legs; for 6 chickens, it's 6 x 2 = 12 legs; for 3 fish, it's 0 legs; and for 4 ants, it's 4 x 6 = 24 legs. Adding them together gives 12 + 12 + 0 + 24 = 48 legs altogether.
-2x/3 - 5 = 5 Add 5 to both sides: -2x/3 = 10 Multiply both sides by 3: -2x = 30 Divide both sides by -2: x = -15
4n-3=5 add 3 both sides 4n=8 divide by 4 both sides n=2
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
2 + 4/a = 14/a - 3 Add 3 to both sides: 5 + 4/a = 14/a Subtract 4/a from both sides: 5 = 10/a Multiply both sides by a: 5a = 10 Divide both sides by 5: a = 2
The least number of spiders and ants that would have an equal number of legs is 3 ants and 1 spider, totaling 24 legs. Each ant has 6 legs, and the spider has 8 legs, resulting in an equal number of legs for both.
ants are in the hexapoda family. hex means six so they have six legs whoopey!
To calculate the total number of legs, we consider each animal's legs: cows have 4 legs each, chickens have 2 legs each, fish have no legs, and ants have 6 legs each. For 3 cows, that's 3 x 4 = 12 legs; for 6 chickens, it's 6 x 2 = 12 legs; for 3 fish, it's 0 legs; and for 4 ants, it's 4 x 6 = 24 legs. Adding them together gives 12 + 12 + 0 + 24 = 48 legs altogether.
1) they are both insects 2) ants have 6 legs 3)the bee has wings but the ant does not. 4)they both have feelers
ants have 3 body sections are either black or red and they have only 6 legs. some have pinchers in front of their mouth. But all of them have antennas also.
Triangle
Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30
2t-6=3-t 3t-6=3 Add t to both sides 3t=9 Add 6 to both sides t=3 Divide both sides by 3
Let the number of ducks be x, so that Robert has 12 - x rabbits. Since rabbits have 4 legs and ducks have 2 legs, we have: 2x + 4(12 - x) = 42 2x + 48 - 4x = 42 -2x + 48 = 42 (subtract 48 to both sides) -2x = -6 (divide by -2 to both sides) x = 3 Thus, Robert has 3 ducks and 9 rabbits.
-2x/3 - 5 = 5 Add 5 to both sides: -2x/3 = 10 Multiply both sides by 3: -2x = 30 Divide both sides by -2: x = -15
4n-3=5 add 3 both sides 4n=8 divide by 4 both sides n=2
3 - f = 6f + 46+f to both sides-------------------3 = 7f + 46- 46 to both sides--------------------43 = 7f÷7 to both sides--------------------43/7 = f