-2x/3 - 5 = 5 Add 5 to both sides: -2x/3 = 10 Multiply both sides by 3: -2x = 30 Divide both sides by -2: x = -15
4n-3=5 add 3 both sides 4n=8 divide by 4 both sides n=2
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
2 + 4/a = 14/a - 3 Add 3 to both sides: 5 + 4/a = 14/a Subtract 4/a from both sides: 5 = 10/a Multiply both sides by a: 5a = 10 Divide both sides by 5: a = 2
n/5 = (n+1)/3 multiply both sides by 5 n = (5n + 5)/3 multiply both sides by 3 3n = 5n + 5 subtract 3n from both sides 0 = 2n + 5 subtract 5 from both sides -5 = 2n divide both sides by 2 n = -2.5
Well, honey, if we're talking about legs here, a spider has 8 legs and an ant has 6 legs. To have an equal number of legs in the group, you'll need to have a multiple of the least common multiple of 8 and 6, which is 24. So, you can have 3 spiders (3 x 8 = 24 legs) and 4 ants (4 x 6 = 24 legs) for a total of 7 critters with 24 legs each.
ants are in the hexapoda family. hex means six so they have six legs whoopey!
1) they are both insects 2) ants have 6 legs 3)the bee has wings but the ant does not. 4)they both have feelers
ants have 3 body sections are either black or red and they have only 6 legs. some have pinchers in front of their mouth. But all of them have antennas also.
Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30Something/3 = 10 Multiply both sides by 3 and that gives:Something = 10 * 3 = 30
2t-6=3-t 3t-6=3 Add t to both sides 3t=9 Add 6 to both sides t=3 Divide both sides by 3
(2x-3)/4 = 9 2x-3 = 36 (multiply both sides by 4) 2x = 39 (add +3 to both sides) x = 19.5 (divide both sides by 2)
-2x/3 - 5 = 5 Add 5 to both sides: -2x/3 = 10 Multiply both sides by 3: -2x = 30 Divide both sides by -2: x = -15
4n-3=5 add 3 both sides 4n=8 divide by 4 both sides n=2
3 - f = 6f + 46+f to both sides-------------------3 = 7f + 46- 46 to both sides--------------------43 = 7f÷7 to both sides--------------------43/7 = f
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
Let the number of ducks be x, so that Robert has 12 - x rabbits. Since rabbits have 4 legs and ducks have 2 legs, we have: 2x + 4(12 - x) = 42 2x + 48 - 4x = 42 -2x + 48 = 42 (subtract 48 to both sides) -2x = -6 (divide by -2 to both sides) x = 3 Thus, Robert has 3 ducks and 9 rabbits.