Those three numbers could be the lengths of the sides of a right triangle,because the squares of two of them add up to the square of the third one.
Using Pythagoras: hypotenuse² = leg_1² + leg_2² = 14² + 48² = 196 + 2304 = 2500 → hypotenuse = √2500 = 50 units.
47, 48, and 49
so 48 is the hypotnuese and 6 is the opposite so that will make sine sine(48 then divide 6 into whatever answer you got for sine(48 and you will see your answer
A right-angled triangle can indeed consist of sides of 20cm, 48cm, and 52cm. 20, 48, 52 are a valid Pythagorean triple, since 202+482=522.
Those three numbers could be the lengths of the sides of a right triangle,because the squares of two of them add up to the square of the third one.
Using Pythagoras: hypotenuse² = leg_1² + leg_2² = 14² + 48² = 196 + 2304 = 2500 → hypotenuse = √2500 = 50 units.
=48
47, 48, and 49
A right triangle with a leg length of 48 inches and a hypotenuse of 80 inches has a third leg of: 64 inches.
so 48 is the hypotnuese and 6 is the opposite so that will make sine sine(48 then divide 6 into whatever answer you got for sine(48 and you will see your answer
Assuming you mean a right angled triangle, I'm pretty sure its 48 degrees.
The sum of the 2 smallest sides of a triangle must be greater than the length of its longest side
A right-angled triangle can indeed consist of sides of 20cm, 48cm, and 52cm. 20, 48, 52 are a valid Pythagorean triple, since 202+482=522.
It's important to remember that a triangle's angles will always total 180 degrees. 180 - 42 - 48 = 90. The last angle is 90 degrees, so this is a right triangle.
67.8822 in.
acute , obtuse obtuse or right angle