No.
The slope of the graph of a direct variation is always positive.
Positive or Negative........I think...
k is the constant of variation and is the gradient (slope) of the relevant graph.
Graphs of direct variation pass through the origin so the y-intercept would be 0.
No, not every relationship whose graph passes through the origin represents direct variation. Direct variation specifically means that the relationship can be expressed in the form ( y = kx ), where ( k ) is a non-zero constant. While a graph passing through the origin indicates a proportional relationship, it can also represent other types of relationships, such as quadratic or polynomial functions, if they contain additional terms. Therefore, the key characteristic of direct variation is the constant ratio between ( y ) and ( x ), not just the point of intersection at the origin.
The slope of the graph of a direct variation is always positive.
yes, a graph of a direct variation must pass through the origin because direct variation is always in form of y=mx where x and y are variables and m is a constant.
Positive or Negative........I think...
equation, table or a graph
k is the constant of variation and is the gradient (slope) of the relevant graph.
Graphs of direct variation pass through the origin so the y-intercept would be 0.
The graph must be linear and pass thru the origin
There are three ways: a table, a graph, and an equation.
It is a straight line passing through the origin.
It is a straight line passing through the origin.
Inverse variation does not pass through the origin, however direct variation always passes through the origin.
For a direct variation, y=kx where k is the constant of variation if x =0 then y=0 and the graph of y=kx passes through the origin. -Indiana Prentice Hall Algebra 2 Text Book.