It depends on who you are trying to call.
A002B07D16 -> binary A 1010 0 0000 0 0000 2 0010 B 1011 0 0000 7 0111 D 1101 A002B07D16 = 1010 0000 0000 0010 1011 0000 0111 11012 10 100 000 000 000 101 011 000 001 111 1012 -> octal 010 2 100 4 000 0 000 0 000 0 101 5 011 3 000 0 001 1 111 7 101 5 10 100 000 000 000 101 011 000 001 111 1012 = 240005301758 A002B07D16 = 24 000 530 1758
001 = one
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
23 times .001 = 0.023
Convert each "digit" of the octal into a triplet of binary digits, according to the following rule: Octal Binary 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 So, for example, octal 53 = binary 101 011 [= decimal 43]
011001.0011102 = 31.168 Simply group the bits in groups of three... 011 001 . 001 110 ... and convert each group to octal.
You need to dial 011 91 and then the 10 digit Indian telephone phone number
input: 76543210(8) output: 111 110 101 100 011 010 001 000(2)
001
001 and then the US number
011
001 then the us number
011-55-11 and then the number
The number between .01 and .001 is .005. This number is found by taking the average of the two given numbers: (.01 + .001) / 2 = .011 / 2 = .005. This calculation represents the midpoint between the two values on the number line.
To call a number in the Republic of Ireland:011 353 + Irish telephone number without any leading zero (for example, to call 01 123456 dial 011 353 1 123456) To call a number in Northern Ireland:011 44 + Northern Irish telephone number without the leading zero (for example, to call 028 99881234 dial 011 44 28 99881234)
001 + code area + phone
001, 002, 003, 004, 005, 010, 011, 012, 013, 014, 015, 020, 021, 022 and 023.