Yes because 64/14 = 6
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∙ 12y ago1 and 7 will go into both numbers evenly leaving no remainders
1 and 7 will go into both numbers evenly with no remainders
One and two will go into both numbers evenly leaving no remainders.
No. 84 is not evenly divisible by 32.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
1 and 7 will go into both numbers evenly leaving no remainders
Each of these numbers will go evenly into 84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
1 and 7 will go into both numbers evenly with no remainders
3 and 1 will go into both number evenly leaving no remainders.
Any number of the form 84*k, where k is an integer, is evenly divisible.
One and two will go into both numbers evenly leaving no remainders.
No. 84 is not evenly divisible by 32.
1 and 3 will go into both numbers evenly leaving no remainders
1, 2, 4 and 8 will go into both numbers evenly with no remainders
Yes. 84 is evenly divisible by seven.
1 and 2 will go into the given three numbers evenly with no remainders
1x14 =14 2x14 =28 3x14 =42 4x14 =56 5x14 =70 6x14 =84 7x14 =98 No.