No, 18 does not go into 7 evenly. When you divide 7 by 18, the result is 0 with a remainder of 7. In other words, 18 cannot be divided into 7 without having a leftover amount.
Twice but there is a remainder of four. or 18/7=2.571428571428571
2*9=18 7*9=63 9 will go into both 18 and 63
18
35 times, remainder 7
7 goes into 127 a total of 18 times, since 7 multiplied by 18 equals 126. This leaves a remainder of 1 when 127 is divided by 7. So, you can express it as 127 = 7 × 18 + 1.
The GCF of 7 and 18 is 1 because 7 is a prime number and seven does not go into 18.
Twice but there is a remainder of four. or 18/7=2.571428571428571
2*9=18 7*9=63 9 will go into both 18 and 63
126 ÷ 7 = 18
18 times132 / 7 = 18.8571429
126, 252
18
10 times, remainder 11
35 times, remainder 7
126 (9 x 14, 7 x 18)
49 there you go
18 divided by 11 equals 1 with a remainder of 7.