1 square yard is the area of a square with 1 yard along each side, that is: 1 sq yd = 1 yd x 1 yd But 1 yd = 3 ft, thus each 1 yd can be replaced by 3 ft, and then multiplied out: 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft
there are 3 ft in 1 yd. therefore, there are 9 ft in 3 yd
Yes, there are 3' in 1 yd
3 ft = 1 yd ⇒ 22 ft = 22 ÷ 3 yd = 71/3 yd ≈ 7.33 yd
1 yd Algebraic Steps / Dimensional Analysis 3 ft*1 yd 3 ft=1 yd
1 yd = 3 ft 1 yd * 1 yd = 1 yd2 = 3 ft * 3 ft = 9 ft2
3 ft = 1 yd 1 sq ft = 1 ft × 1 ft = (1 ÷ 3) yd × (1 ÷ 3) yd = 1/9 sq yd → 100 sq ft = 100 × 1/9 sq yd = 11 1/9 sq yd ≈ 11.1 sq yd
3 yd. 1 ft. is greater.
1 square yard is the area of a square with 1 yard along each side, that is: 1 sq yd = 1 yd x 1 yd But 1 yd = 3 ft, thus each 1 yd can be replaced by 3 ft, and then multiplied out: 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft
1 yd = 3 ft 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft ⇒ 1 sq ft = 1/9 sq yd ≈ 0.11 sq yd
there are 3 ft in 1 yd. therefore, there are 9 ft in 3 yd
It is a volume 1 yd x 1 yd x 1 yd or 3 ft x 3 ft x 3 ft.
Yes, there are 3' in 1 yd
3 ft = 1 yd ⇒ 22 ft = 22 ÷ 3 yd = 71/3 yd ≈ 7.33 yd
3 yd. 1 ft. is greater.
36 in = 1 yd → 3 in = 3 ÷ 36 yd = 1/12 yd ≈ 0.083 yd
There are 3 ft in 1 yd ... SO (3 ft/yd) x 1760 yd = 5,280 ft (which equals 1 US mile)