No.
To be divisible by 6 the number must be divisible by both 2 and 3.
To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2.
To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3.
As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
Yes. But not evenly.
No. 35/3 = 11.667
No. 35 is not evenly divisible by two.
No. 144 is not evenly divisible by 35.
No. 35 is not evenly divisible by 21.
No. 35 is not evenly divisible by 475.
7
56 is not a multiple of 35
Allow 6 to go into 35 evenly, then figure out the remainder. For example, 6*5 = 30 and then there is 5 left over so the mixed number is 5 and 5/6
708 does not go into six evenly.
35 times.
No - 100/35 = 2.857142 recurring (that is, 2.857142857142...)