Yes but it will have remainder
21.5
129
1,3,14,88,89, and 129
No. All multiples of 6 are even and 129 is odd so it cannot be divisible by 6.
129 does not go into 20 at all, as 20 is less than 129. In terms of whole numbers, 129 goes into 20 zero times. If you were to divide 20 by 129, you would get a decimal result of approximately 0.155.
no
No, it cannot. Just these: 1, 3, 43, 129.
21
6 times, remainder 15
6 ÷ 129 = 0.046511628
21.5
129
Twelve of them
129 times 10 to the negative 6 (129 x 10-6) in standard notation = 0.000129
1,3,14,88,89, and 129
No. All multiples of 6 are even and 129 is odd so it cannot be divisible by 6.
These are all the whole numbers that go into 129 evenly: 1, 3, 43, 129.