You can't. 19 - 1 = 18, not 20.
Volumes 1 and 2 are for diagnosis codes Volume 3 is for procedures
If the ratio of side lengths is 49 (that is 49 to 1) then the ratio of their volumes is 493 to 1, which is 117,649 to 1.
The ratio of the volumes of two similar spheres is the cube of the ratio of their radii. If the ratio of their radii is 59:1, then the ratio of their volumes is ( 59^3:1^3 ), which is ( 205379:1 ). Thus, the volume ratio of the two spheres is 205379:1.
Although it's been a while, I am nonetheless almost irresistibly temptedto rush in here, where so many others might fear to tread.I'll asume that I0 and Y0 are the least significant digits on both sides.Then Y3 = 1 when I8 or I9 = 1 . Then the output is [ 1000 ] or [ 1001 ] respectively.So now I have to dredge up how to say that in Boolean.How about . . .Y3 = (I8 + I9) (not-I0 not-I1 ..... not-I6 not-I7)or the equivalent . . .Y3 = (I8 + I9) AND NOT(I0 + I1 + ..... + I6 + I7)But wait ! All of the lower decimal input lines ARE zero when theinput is 8 or 9, so I don't have to specify them.Y3 is just (I8 + I9) .Sometimes I amaze myself. What else could my hard-drive haveaccomodated, if only I had deleted this stuff 50 years ago. I feltthat I'd need it some day, and ... son of a gun ... I did, just now !
If you mean i9, or -i9, or even (-i)9, no - it isn't. The powers of i are: i, -1, -i, 1, i, -1, -i, 1, ... Whereas the powers of (-i) are: -i, -1, i, 1, -i, -1, i, 1, ... The pattern repeats in both cases. In other words, all even powers of i (or of (-i)) are real numbers; all odd powers are pure imaginary numbers.
You can't. 19 - 1 = 18, not 20.
3 volumes
Book 1 has 5 volumes. Books 2 and 3 have four
There are 5 volumes in Book 1, each containing 5 episodes.
There are 8 volumes. I know this because of wikipedia. Volumes 1-3 are out, but volume 4 will be out in September 2011. Hope I helped!
1
Volumes 1 and 2 are for diagnosis codes Volume 3 is for procedures
1.
3.
Equal volumes (1 to 1) for each mole of any gas (doesn't matter what kind of).
If the ratio of side lengths is 49 (that is 49 to 1) then the ratio of their volumes is 493 to 1, which is 117,649 to 1.