f(x) = x2 + 4x - 5 ( a minimum since the coefficient of x2 is positive, the parabola opens upward)
f'(x) = 2x + 4
f''(x) = 2
At a maximum or minimum, f'(x) = 0
2x + 4 = 0
2x = -4
x = -2
f(-2) = 4 - 8 - 5 = -9
The stationary point occurs at (-2, -9)
f''(-2) = 2
The second derivative is positive at this point, so the gradient is becoming more positive. This means that before this point the gradient was negative and after this point the gradient is positive, so the point is a minimum.
Chat with our AI personalities
There is no maximum but te minimum is 15.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
It is a quadratic function which represents a parabola.
Only if it's a function.
No.