f(x) = x2 + 4x - 5 ( a minimum since the coefficient of x2 is positive, the parabola opens upward)
f'(x) = 2x + 4
f''(x) = 2
At a maximum or minimum, f'(x) = 0
2x + 4 = 0
2x = -4
x = -2
f(-2) = 4 - 8 - 5 = -9
The stationary point occurs at (-2, -9)
f''(-2) = 2
The second derivative is positive at this point, so the gradient is becoming more positive. This means that before this point the gradient was negative and after this point the gradient is positive, so the point is a minimum.
There is no maximum but te minimum is 15.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
It is a quadratic function which represents a parabola.
Only if it's a function.
No.
There is no maximum but te minimum is 15.
The answer will depend on the ranges for x and y. If the ranges are not restricted, then C can have any value.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
A straight line has no turning points and so no local maxima or minima. The line has a maximum at + infinity and a minimum at - infinity if m > 0 and conversely if m < 0. When m = 0, the line is horizontal and so has no maximum or minimum. ([Alternatively, every point on the line is simultaneously a maximum and a minimum.]
5 7
Potassium's minimum oxidation number is zero.Its maximum is plus one.
(x-2) is not a factor of the numerator and so y tends to minus infinity as x approaches 2 from below. As x approaches 2 from above, y tends to plus infinity. There are, therefore, no maximum or minimum values for y.
It is a quadratic function which represents a parabola.
The question is not clear. A function is defined by an equation and that requires an equals sign. there is no equals sign in the question. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".
Only if it's a function.
Yes.
yes