they have both.Sometimes they have 6 and sometimes 8
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(4t2 - 16)/8 ÷ (t - 2)/6 = [4(t2 - 4)/8] x 6/(t - 2) = (t2 - 22)/2 x 6/(t - 2) = (6/2)[(t + 2)(t - 2)/(t - 2)] = 3(t + 2) = 3t + 6
-8+5T=-6 add 8 to each side 5T =8-6 5T=2 T=2/5 or T=0.4
8. To solve this problem, plug the given t value into the equation. So, given the equation 7t-6 and that t=2, I get 7(2) - 6. This is the same as 14-6, which is 8
t+8 = 2-3t add 3t to both sides: 4t+8 = 2 take 8 away from both sides: 4t = -6 divide both sides by 4: t = -6/4 = -3/2
t is equal to 6