yes it does!
A sphere's height will always be the same as its diameter.
The radius of a sphere is 1/2 of its height.
Your measurements are not those of a sphere. The 12 inches and 6 inches are OK, but if it's a sphere, its height would equal the diameter and be equal to 12 inches. Please repost your question and change either the height or the word, "Sphere".
Vol = 4/3*pi*r3 so given the volume, you can calculate the radius. Height of sphere = 2*radius.
A sphere of radius 12 inches cannot have a height of 23 inches. It is, in that case, a flattened sphere and a lot more detailed information about the flattening is required to find its volume.
A sphere's height will always be the same as its diameter.
The radius of a sphere is 1/2 of its height.
If the radius is 7 and the volume is 1232 the shape cannot be a sphere so you cannot find the height of a sphere when the shape is not a sphere!
A sphere is three-dimensional. It has height, width and depth.
Your measurements are not those of a sphere. The 12 inches and 6 inches are OK, but if it's a sphere, its height would equal the diameter and be equal to 12 inches. Please repost your question and change either the height or the word, "Sphere".
Vol = 4/3*pi*r3 so given the volume, you can calculate the radius. Height of sphere = 2*radius.
A sphere of radius 12 inches cannot have a height of 23 inches. It is, in that case, a flattened sphere and a lot more detailed information about the flattening is required to find its volume.
I can't really believe you're asking this.What's the difference between height, width or diameter when the object is a sphere?It measures the same all over.The diameter IS the height, and the width, and the depth.
A sphere with a radius of 5 has a volume of: 523.6 cubic units.
I'm quite sure this is impossible to prove, because the volume of a sphere is not equal to the volume of a cylinder with the same radius and height equal to the sphere's diameter. This can be shown as: Volume of sphere = (4*pi*r3) / 3. Volume of cylinder = pi*r2*h. Here, the height, h, of the cylinder = d = 2r. So, the volume of the cylinder = pi*r2*2r = 2*pi*r3, which obviously does not equal the volume of the sphere. The volume of half a sphere (with radius r) is equal to the volume of a cylinder(whose height is equal to its radius, r) minus the volume of a cone with the same height and radius. Therefore, the volume of a sphere is just double that. If you follow the nearby link, you can see a nice demonstration of that.
The height of the cone of maximum volume that can be inscribed in a sphere of radius 12 cm is not 16 cm; it is actually 16 cm when considering the relationship between the cone's dimensions and the sphere's radius. The cone's volume is maximized when its height is two-thirds of the sphere's radius, which means the optimal height is ( \frac{2}{3} \times 12 \text{ cm} = 8 \text{ cm} ). Thus, the statement is incorrect; the correct height for maximum volume is 8 cm, not 16 cm.
The ancient Greek mathematician Archimedes proved that the volume of a sphere is four times that of the cone with base equal to a great circle of the sphere and height the radius of the sphere. Maybe this is what the poser of the question meant.