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The axis of the sphere below is 12 units in length What is the surface area of the sphere?
144pi units squared
What is the surface area of the sphere with 12 units in length?
Surface area of a sphere = 4*pi*radius^2
What is the surface area of the sphere with length of 16 units?
Surface area of a sphere = 4*pi*radius squared
What is the surface area of a sphere with 12 units in length?
Surface area of a sphere is: 4*pi*radius squared
Volume for a sphere?
Radius times length times .33
How do you find true length of a sphere?
The length of a sphere is its diameter
What is the characteristic length of a sphere and how does it affect the sphere's properties?
The characteristic length of a sphere is its diameter, which is the distance across the sphere passing through its center. The characteristic length affects the sphere's properties such as volume, surface area, and density. A larger characteristic length means a larger volume and surface area, while a smaller characteristic length means a smaller volume and surface area.
The axis of the sphere below is 12 units in length what is the surface of the sphere?
144pi units2
How do you find base of a sphere with a given volume?
The base of a sphere is a single point: with no length or breadth.
What axis of the sphere below is 16 units in length What is the surface area of the sphere?
The answer is given below.
What is the side length of a cube that has the same volume of a sphere with the radius of 1?
The side length of a cube that has the same volume of a sphere with the radius of 1 is: 1.61 units.
The axis of the sphere below is 12 units in length What is the surface area of the sphere?
144pi units squared
What is the surface area of the sphere with 12 units in length?
Surface area of a sphere = 4*pi*radius^2
What is the surface area of the sphere with length of 16 units?
Surface area of a sphere = 4*pi*radius squared
What is the surface area of a sphere with 12 units in length?
Surface area of a sphere is: 4*pi*radius squared
Volume for a sphere?
Radius times length times .33
How do you find the empty space if you put a sphere in a cube?
Vol(cube) = length(diameter)^(3) Volume(sphere) = (4/3) pi* radius^(3) Now the radius is '1/2 ' the diameter/length , assuming as 'perfect' fit. So substituting Vol(cube) = (2radii)^(3) = (2r)^(3) To find the 'Ullage' unused space, subtract one from the other. Vol(cube) - Vol(sph). (2r)^(3) - (4/3 pi*r^(3) Factor r^(3) [ 2^(3) - (4/3 pi ] => 4r^(3) [ 2 - pi/3] NB ' pi = 3.141592..... So all you need is to find the length of one side of the cube and halve it. So if the cube is 64 units^(3) Then the side length is the cube root of 64 units^(3) , which is 4units. Half of this side length is 2 units ( 4/2) , this is the radius(r). Substituting Ullage space is 4(2)^(3) [ 2 - 3.14 / 3] ==> 4(8)[ 2 - 1.047...] 32[ 2 - 1.047...] 32[ 0.9529...] == > 30.9438.... units^(3) is the volume of the Ullage space.
