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The probability of a hand containing one or more aces is equal to 1 minus the probability of the hand not containing any aces. The probability for each card will be 48/52 multiplied by 47/51 multiplied by 46/50 and so on. This gives 0.30382 1 minus this is 0.696 Therefore the probability of a 13-card hand containing one or more aces is 0.696
11 / 7 is equal to 1.57 or 1 57/100
12
33 and 1 -33 and -1 11 and 3 -11 and -3
11