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Algebraically, what you're asking is if there is a value for x such that x-1 = (1/2)x. Well, let's solve for x and see.
First, multiply both sides by x:
x*x-1 = (1/2)x*x, 1 = (1/2)x2.
Then, multiply both sides by 2:
2*1 = 2*(1/2)x2, 2 = x2.
Finally,take the square root of both sides:
√(2) = √(x2), which leaves us with two numbers that satisfy your question,
x = ±√2.
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