Algebraically, what you're asking is if there is a value for x such that x-1 = (1/2)x. Well, let's solve for x and see.
First, multiply both sides by x:
x*x-1 = (1/2)x*x, 1 = (1/2)x2.
Then, multiply both sides by 2:
2*1 = 2*(1/2)x2, 2 = x2.
Finally,take the square root of both sides:
√(2) = √(x2), which leaves us with two numbers that satisfy your question,
x = ±√2.
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The absolute value of any negative number is equal to its positive equivalent, that is, the number without its negative sign. In this instance, abs(-54) is equal to 54.
Yes, almost half of them have additive inverses which are negative.
5
any number below negative 1
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.