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The eyepiece is usually 10x, so multiply the objective by 10 to get true magnification
Let the larger side be 4x and and the shorter side be x: 2(4x+x) = 150 8x+2x = 150 10x = 150 x = 15 Therefore the length of the shorter side is 15 units.
10x + 13 = 1710x = 17-1310x = 4x = 4/10x = 0.4
10x and 6y are terms of an algebraic expression
10x - 3y + 2x - 4y =(10x + 2x) + (-3y - 4y) =12x - 7y