Since the perimeter is a linear measure it is also doubled.
A square has all 4 of its perimeter lengths equal. Thus the length of the perimeter divided by 4 will give you the 'unitary' dimension. Multiply this 'unitary' dimension by itself (square it) and the result is the area of the square in question.
Perimeter of 12" by 8" = 12+8+12+8 = 40 inches.
14.734375
28 feet
Since the perimeter is a linear measure it is also doubled.
If you double the diameter, or the radius, then the perimeter will also double.
A square has all 4 of its perimeter lengths equal. Thus the length of the perimeter divided by 4 will give you the 'unitary' dimension. Multiply this 'unitary' dimension by itself (square it) and the result is the area of the square in question.
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
Perimeter of 12" by 8" = 12+8+12+8 = 40 inches.
14.734375
28 feet
If you double the dimensions, then the perimeter is doubled. However, the area is quadrupled. For example, let's say that a side of a square is x units. The perimeter would be 4x, and the area x2. Now, let's double the dimension into 2x. Now, the perimeter is 8x, and the area is 4x2. As you can see, the perimeter is doubled and the area is quadrupled.
There is no such thing as the area of the perimeter. A perimeter is a length and so has only 1 dimension. As such, its area is 0.
12' x 10'
quadruples it
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).