No, y+2=x does not show direct variation. In direction variation you need to be able to multiply y by something to get x. In the question y+2=x, you have to add 2 to y to get x, which is not multiplying.)
No, the expression ( y - 2x ) does not represent direct variation. In a direct variation, the relationship between two variables can be expressed in the form ( y = kx ), where ( k ) is a constant. The equation ( y - 2x = 0 ) can be rearranged to ( y = 2x ), which does show direct variation, but the original expression itself does not imply this relationship without further context.
Yes. y = 1x is the same as y = x which is the simplest case of direct variation. If you consider the equation y = mx + b, then a direct variation will always have b = 0 (i.e. the graph goes through the origin). The value of m is called the "constant of variation", and the equation is usually written as y = kx.
To determine if ( xy^3 ) shows direct variation, we check if it can be expressed in the form ( y = kx ), where ( k ) is a constant. In the case of ( xy^3 ), it is more appropriate to analyze it as a function of ( y ): if we isolate ( y ), we find ( y^3 = \frac{k}{x} ), indicating that ( y ) varies inversely with ( x ). Therefore, ( xy^3 ) does not show direct variation.
x = 0 & y = -3
4
No, it does not.
No. Direct variation describes a relationship between two variables. It has nothing to do with the value of a single number.
No, the expression ( y - 2x ) does not represent direct variation. In a direct variation, the relationship between two variables can be expressed in the form ( y = kx ), where ( k ) is a constant. The equation ( y - 2x = 0 ) can be rearranged to ( y = 2x ), which does show direct variation, but the original expression itself does not imply this relationship without further context.
you have to find the key with the plus and equals symbol. Then push the shift key and the plus/equals key. The "cross" should show up. Plus (+) equals (=). The plus should be above the equals.
Yes. y = 1x is the same as y = x which is the simplest case of direct variation. If you consider the equation y = mx + b, then a direct variation will always have b = 0 (i.e. the graph goes through the origin). The value of m is called the "constant of variation", and the equation is usually written as y = kx.
To determine if ( xy^3 ) shows direct variation, we check if it can be expressed in the form ( y = kx ), where ( k ) is a constant. In the case of ( xy^3 ), it is more appropriate to analyze it as a function of ( y ): if we isolate ( y ), we find ( y^3 = \frac{k}{x} ), indicating that ( y ) varies inversely with ( x ). Therefore, ( xy^3 ) does not show direct variation.
Algebra4y-4 plus y plus 24 equals 6y plus 20-4YCombine like terms5y+20=2y+20Isolate Y3y=0y=0
x = 0 & y = -3
There are 2 unknowns
b/2=2ab/+b means112.5
4
bend over and ill show you