To find out how many square inches of the wall will be covered with kites, first calculate the area of one kite. The area of a kite is given by the formula ( \text{Area} = \frac{1}{2} \times d_1 \times d_2 ), where ( d_1 ) and ( d_2 ) are the lengths of the diagonals. Here, ( d_1 = 6 ) inches and ( d_2 = 12 ) inches, so the area of one kite is ( \frac{1}{2} \times 6 \times 12 = 36 ) square inches. The wall's area is ( 12 \text{ feet} \times 12 \text{ inches/foot} = 144 \text{ inches} ), resulting in a total wall area of ( 144 \times 12 = 1728 ) square inches. If we divide the wall's area by the area of one kite, ( 1728 / 36 = 48 ), meaning 48 kites can cover the wall. Thus, the total area covered by kites on the wall is ( 48 \times 36 = 1728 ) square inches.
Cubic inches measures volume. Square inches measures area. Therefore, you can not compare the two. It is like comparing feet and cups.
3.141 square inches
It is: 7*7 = 49 square inches
A square with a side length of 6 inches has an area of 36 square inches.
There is no such thing as a square whose length and width are different.
Cubic inches measures volume. Square inches measures area. Therefore, you can not compare the two. It is like comparing feet and cups.
The question makes no sense. Square feet measures area. Inches measures length. There are, however, 7.76 square feet in in 1118 square inches. (Divide by 12x12.)
3.141 square inches
The area is 144 square inches.
It is: 7*7 = 49 square inches
4 inches x 4 inches = 16 square inches
A square foot measures 12 inches by 12 inches - which equals 144 square inches. That means that 1152 square inches = 1152/144 = 8 square feet.
The squares for this quilt will need to be 8 1/2 inches, that includes the 1/4 inch seam allowance for stitching them together. The finished blocks will be 8 inches square.
There are 61.1 square feet in an area that measures 66x100 inches.
A square with a side length of 6 inches has an area of 36 square inches.
238.6 square feet.
There is no such thing as a square whose length and width are different.